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[tex]4\sqrt 3 . (3\sqrt5 +\sqrt45 ) : 13 \sqrt5 - \sqrt5[/tex]

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Hilalmelekrans
[tex]4\sqrt{3}.( 3\sqrt{5} + \sqrt{45}): 13\sqrt{5} - \sqrt{5} [/tex]=

[tex] 4\sqrt{3} (3 \sqrt{5} +3 \sqrt{5} ): 12 \sqrt{5} [/tex]

[tex] 4\sqrt{3} . 6 \sqrt{5} : 12 \sqrt{5} = \frac{4 \sqrt{3} }{2} =2 \sqrt{3} [/tex]

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