Answered

Q(3x-5)=P(x-2)-Q(X-3) ve P[(x+1)(x-1)]=2x²+10 ise Q(x) polinomunun x+2 ile bölümünden kalan nedir ? lütfeen cevaplayın

Sagot :

x+2=0 x=-2 için

3x-5=-2  3x=3 x=1

Q(3.1-5)=P(1-2)-Q(1-3)

Q(-2)=P(-1)-Q(-2)

P(xkare-1)=2xkare+10  xkare-1=-1 xkare=0(xkare gördüğümüz yere 0 yazacağız)

P(-1)=10

Q(-2)=10-Q(-2)

2.Q(-2)=10

Q(-2)=5

 

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