Sagot :
sayılar x,x+1,x+2.... olursa ilk üç x+x+1+x+2:63 yani 3x+3:63 burdan x:20 çıkar son üç terim son üç terim x+7,x+8,x+9 toplamı 3x+24 : 3.20+24: 84tür
arkadaşım 63 ardışıkları = 20+21+22 dir yani 10 tane diyorsun.
20+21+22+23+24+25+26+27+28+29 son 3 sayı =27,28 ,29, =84 olur
Thank you for visiting our website wich cover about Matematik. We hope the information provided has been useful to you. Feel free to contact us if you have any questions or need further assistance. See you next time and dont miss to bookmark.