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z=1+cos40+i sin40 ise |z| nedir arkadaşlar? 11. sınıf

 

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z=-(1+cos40+isin40)=-(1+2coskare20-1+2isin20cos20)=
-(2cos20(cos20+isin20))=-cos20-isin20=cos(180+20)+isin(180+20)
=cos200+isin200=cis200
argz=200 olur.
(2cos20 sabit bir sayı olduğundan dikkate almaya gerek yoktur.)
yarımaçı formülleri kullanarak çözüm yapılır.

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