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s(A\B)=10 s(A)=2 s(B) ve s(A kesişim işareti B)=4 olduğuna göre,s(A)+s(B) kaçtır?

Sagot :

s(A\B)=10 ..x = 10

s(A)= 10+4 =14

s(A)=2 s(B)....14=2 s(B)... s(B)=7

istenen s(A)+s(B)=14+7=21

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Edanurbaserrans

   cevabı  A :14 B :7  toplamı 21

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