[tex](3^{-1}+2^0)^{-1}:12 = (\frac{1}{3}+1)^{-1}:12=(\frac{4}{3}):12=\frac{4}{3.12}=\frac{1}{9}[/tex] bu tip kesir sorularında işlemlere dikkat etmek gerekir en ufak hatada kesir problemleri problem olabilir :)
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