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(p=>q)^q')=>q' önermesinin en sade şeklini bulunuz.

Sagot :

Buraknalbantoğlurans

(p'vq)ve q')ise q'

(q' v q)ve p')ise q'

q ve p' => q'

(q ve p')' =>q'

q've p v q'

 

(q' ve q') v p

 

CEVAP:  q' v p

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