0,1 mol N₂ gazı ile yeterli miktarda H₂ N₂ + 3H₂ ->>> 2NH3 A) 1.7 en fazla opwks 4 frimeageco B) 3,4 slopw5s3frimeage C) 5,1 553frimealer 78712 gram NH3 D) 6,8 oluşturur? (H:1, N:14) Dec0218712
Sagot :
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