B
E
A) √3
3k
X
B) 3
A
D
4√2
C) 2√3
[AB] [AC]
[AD] [DE]
|AE| = 3|EB|
|BD| = |DC|
|AC| = 4√2
C ⇒ |ED| = x= ?
D) √6
E) 6
Sagot :
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