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3a-[(4a-4)- (5a+5) + 4a] + 1 ifadesinin esiti nedir?

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Sagot :

3a-[(4a-4)- (5a+5) + 4a] + 1 = 3a-[4a-4-5a-5+4a]+1=3a-[3a-9]+1=3a-3a+9+1=10

Alpunemrerans

köşeli parantez içini önce hallederiz : 4a-4-5a-5+4a =3a-9    şimdi hepsini baştan yazalım : 3a-(3a-9)+1 =10

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