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a+b+c+d / 2 < a+b+c+d+34 / 3 eşitsizliğinin a+b+c+d türünden cevabı nedir? ​

Sagot :

Berkanerezrans

Cevap:

[tex] \frac{a + b + c + d}{2} < \frac{a + b + c + d + 34}{3} [/tex]

Caprazlama yap

3a+3b+3c+3d<2a+2b+2c+2d+68 olur bu da

A+b+c+d<68 olur

Buda cevabı

[ eksi sonsuzdan , 67] ye kadar olur

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