Answered

0,4 mol HCOOH ve 0,1 mol HCOONa tan oluşan 1 litrelik tampon çözeltisinin 25°C ’deki pH değerini hesaplayınız (Ka=1,8x 10-4 ).

Sagot :

Drkardanadamrans

Cevap:

3,1427

Açıklama:

[[tex]H^{+}[/tex]]=Ka×[Asit]/[Tuz]

[Asit]=0,4mol/1litre = 0,4M

[Tuz]=0,1mol/0,1litre = 0,1 M

[[tex]H^{+}[/tex]]=(1,8×[tex]10^{-4}[/tex])×0,4/0,1

[[tex]H^{+}[/tex]]=7,2×[tex]10^{-4}[/tex]

pH=-log(7,2×[tex]10^{-4}[/tex])

pH=3,1427

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