Sagot :
3lu esitligi ikilik parcalara boleceksin
ab/3=BC/4
4AB/12=3BC/12 ... 12 VE Bler gider.
4a=3c
bc/4=ac/5
5bc/20=4ac/20
5b=4a
ikisi yetiyor.
5b=4a=3c=60k (60 ekok ancak bize ortak katlarin en kucugu degil belirli bir tanesi lazim. o yuzden k bilinmeyeni ile carpim halinde gosteriyoruz ekoku)
b=60k/5=12k
a=60k/4=15k
c=60k/3=20k
a+b+c=(12+15+20)k=47k=94
k=2
b=12k=12×2=24
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