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(ab),(ba),(cd),(dc) iki basamaklı doğal sayılardır. a+d = 7 , c+d = 6 veriliyor 
(ab) + (ba) + (cd) + (dc) kaçtır?

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ab= 10a+b

ba= 10b+a

cd= 10c+d

dc= 10d+c   dir.

 

Bu sayıların toplamı ise 11a+11b+11c+11d = 11(a+b+c+d) = 11.(7+6)=143 tür.

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