Answered

kökleri 3-√2ve3+√2 olan ikinci dereceden denklem nedir​

Sagot :

Cirtcirthooprans

Cevap:

x*-6x+7

Adım adım açıklama:

x`-6x+7 dir bu denklemim deltasına bakicak olursak

36-4.7.1 den

[tex] \sqrt{8} [/tex]

çıkardeltalı kök bulma formülü ise

[tex] - b \: - + \sqrt{ \beta } \div 2a \: [/tex]

Bu förmüle uyuyor

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