Sensizalem44rans
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p=>[(q'=>p)^p] önermesinin doğruluk değerini bulunuz...

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Cihan593rans

p'vq cevap ama işlem yaparak uzun sürer

p=>[(q'=>p)^p]

 

P' v [(qVp)^p]
p'v(qVp)^P
qv(p'vp)^p
qv (1) ^ p

qv1 = 1
1 ^ p = p 

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