Answered

C(n,3) /bölü/ C(n,4)=4/bölü/3 olduğuna göre n kaçtır?
(kesirli kombinasyon sorusu)

Sagot :

Drkardanadamrans

Cevap:

Adım adım açıklama:

[n.(n-1).(n-2)/6] ÷ [n.(n-1).(n-2).(n-3)/24] = 4/3

n.(n-1).(n-2) sadeleşir.

[1/6] ÷[(n-3)/24]=4/3

24/(6.(n-3))=4/3

n-3=3 => n=6 olur.

Sağlama:

C(6,3)=20 Ve C(6,2)=15

20/15=4/3

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