Cevap:
[tex] \frac{ {2}^{x + 4} + {2}^{x + 3} }{ {2}^{x - 2} + {2}^{x - 3} } = \frac{ {2}^{x} . {2}^{4} + {2}^{x} . {2}^{3} }{ {2}^{x} . {2}^{ - 2} + {2}^{x} . {2}^{ - 3} } \\ = \frac{ {2}^{x}( {2}^{4} + {2}^{3} ) }{ {2}^{x} ( {2}^{ - 2} + {2}^{ - 3}) } \\ = \frac{16 + 8}{ \frac{1}{4} + \frac{1}{8} } \\ = \frac{24}{ \frac{3}{8} } \\ = 24. \frac{8}{3} \\ = 8.8 \\ = 64[/tex]
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