Sagot :
Cevap:
B ŞIKKI 30
Adım adım açıklama:
İLK SAYI X OLSUN HER SEFERİNDE ARDIŞIK ÇİFT OLDUĞU İÇİN İKİŞER ARTAR.
1.X
2.X+2
3.X+4 BU 4 SAYININ ARİTMETİK ORTALAMASI; (4X+12)/4=33
4.X+6 4X+12=4.33= 132 4X=120 X=30 ( EN KÜÇÜK SAYI)
+______
4X+12
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