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[tex]\int sin(2x)cos(2x)dx=?[/tex]Saygılar,1346526851test

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Marmagusrans

u=sin(2x)

du=2cos(2x)dx

 

1/2du=cos(2x)dx

 

integral( u (1/2) du )
=(1/2) integral ( u du )
(=1/2) (1/2)u^2 + C
=(1/4)u^2 + C        

 

u=sin(2x) di ==>(1/4) sin^2(2x) + C bulunur.

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