Cevap:
[tex]C)x\in [1,27)[/tex]
Adım adım açıklama:
[tex] \displaystyle 1 \leq \frac{3x + 5}{8} < 7[/tex]
[tex] \displaystyle \implies 8 \leq 3x + 5 < 56[/tex]
[tex] \displaystyle \implies 3 \leq 3x < 51[/tex]
[tex] \displaystyle \implies \frac{3}{3} \leq \frac{3x}{3} < \frac{51}{3} \\ \implies 1 \leq x < 17 \implies \boxed{x \in[1,17) }[/tex]
