In closed container with constant volume, equal masses of He, CH4 and SO2 gases create a total pressure of 4.2 atm.
what is the partial pressure of CH4 gas?
Hi guys by Kim biliyor?​


Sagot :

Cevap: 0,8 atm

Açıklama:

1- We have a closed container with a constant volume so in the equation of ideal gas formula we can ignore the "Volume" "R" and the Temperature "T" so now we have
[tex]"P. V=n.R.T = P= n"[/tex]

that means we can calculate the total pressure with "n"s of the three elements we are using: "He" "[tex]CH_{4}[/tex] " and "[tex]SO_{2}[/tex]"

2- It says that all elements have equal masses so let's call it "m" grams
We already now that 1 moles of He equals to 4 grams while 1 moles of [tex]CH_{4}[/tex] equals to 16 and 1 moles of [tex]SO_{2}[/tex] equals to 64 grams.

now let's get back to our [tex]P=n[/tex] equation.

3- We can use this equation to calculate the total pressure in a closed container: [tex]P_{total} = P_{He} +P_{CH_{4} } +P_{SO_{2} }[/tex]

Pressures of the elements in the closed container equals to their mole masses therefore total pressure is equal to total masses of moles.
[tex]P_{total} = N_{He} +N_{CH_{4} } +N_{SO_{2} }[/tex]

now we can solve the equation and find the partial pressure of [tex]CH_{4}[/tex] (partial pressure of an element is also equals to its mole mass. so we will  need the mole mass of [tex]CH_{4}[/tex])

4- [tex]4,2=\frac{m}{4} +\frac{m}{16} +\frac{m}{64}[/tex] ⇒[tex]m = 12,8[/tex]

So we have found the "m", we now know that all elements are 12,8 grams. Let's find the partial pressure of [tex]CH_{4}[/tex]:

[tex]\frac{m}{16} =N_{CH_{4} } = P_{CH_{4} }[/tex]
⇒ [tex]\frac{12,8}{16} = P_{CH_{4} } = 0,8 atm[/tex]