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ab ve cd iki basamkli dogalsayilardir d-b=4 a-c=2 olduğuna göre ab-cd farki kaçtır
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ab → 10a+b

cd → 10c+d

ab-cd = 10a+b-(10c+d) = 10a+b-10c-d

Ortak paranteze alırsak: 10.(a-c) + b-d

a-c = 2 olarak verilmişti zaten.

d-b = 4 ise b-d = -4'tür.

10.(a-c)+b-d = 10.(2)-4

→ 20-4 = 16

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