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3x - {2x-3[(x - 2)-3]+ 3x}=9x - 20
ise, x değerl kaçtır?

A) 1/8

B)3/8

C)5/8

D)7/8

Sagot :

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  • [tex]3x - (2x - 3(x - 5) + 3x) = 9x - 20 \\ 3x - (2x - 3x + 15 + 3x) = 9x - 20 \\ 3x - (2x + 15) = 9x - 20 \\ 3x - 2x - 15 = 9x - 20 \\ x - 15 = 9x - 20 \\ 8x = 5 \\ x = \frac{5}{8} [/tex]

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5/8


3x-(2x+15)=9x-20

x-15= 9x-20

x-15-9x=-20

-8x=-20+15

-8x=-5

x=3/8
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