Sagot :
a2=3
a7=96
r=ortak fark
[tex]a7 = a2. {r}^{5} [/tex]
[tex]96 = 3. {r}^{5} [/tex]
[tex] {r}^{5} = 32 = {2}^{5} [/tex]
r=2
[tex]a10 = a7. {r}^{3} [/tex]
[tex]a10 = 96. {2}^{3} [/tex]
a10=96.8
a10=768
- Başarılar...
Cevap:
768
Adım adım açıklama:
96/3=32
32^(2-7)=32^(-5)=2 => geometrik artış oranı 2 dir.
10. Terim = 3.2^(10-2)=3.2^8=3.256=768
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