Pinaaarrans
Answered

P(x)= 3x(üzeri dört)-2x²+x+4 

 

Q(x)=5x²+4x+1 ise  

 

P(x).Q(x)=?

Sagot :

MaTeMaTiKkrans

P(x).Q(x)= (3xüssü4-2x²+x+4).(5x²+4x+1)

15xüssü6+12xüssü5+3xüssü4-10xüssü4-8üssü3-2xüssü2+5xüssü3+4xüssü2+x+20xüssü2

                                                                                                                   +16x+4

=15xüssü6+12xüssü5-7xüssü4-3üssü3+22üssü2+17x+4

Şahrans

P(x).Q(x)= (3[tex]x^{4}[/tex]-2[tex]x^{2}[/tex]+x+4).(5[tex]x^{2}[/tex]+4x+1)

 

=  (3[tex]x^{4}[/tex].5[tex]x^{2}[/tex])+(3[tex]x^{4}[/tex].4x)+(3[tex]x^{4}[/tex].1) - (2[tex]x^{2}[/tex].5[tex]x^{2}[/tex]) - (2[tex]x^{2}[/tex].4x) - (2[tex]x^{2}[/tex].1) + (x.5[tex]x^{2}[/tex])+(x.4x)+(x.1)+(4.5[tex]x^{2}[/tex]) +(4.4x)+(4.1)

 

= (15[tex]x^{6}[/tex])+(12[tex]x^{5}[/tex])+(3[tex]x^{4}[/tex])-(10[tex]x^{4}[/tex])-(8[tex]x^{3}[/tex])-(2[tex]x^{2}[/tex])+(5[tex]x^{3}[/tex])+(4[tex]x^{2}[/tex])+(x)+(20[tex]x^{2}[/tex])+(16x)+(4)

 

cevap

=(15[tex]x^6[/tex])+(12[tex]x^{5}[/tex])-(7[tex]x^{4}[/tex])-(3[tex]x^{3}[/tex])+(22[tex]x^{2}[/tex])+17x+4

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