Sagot :
a-b=5
a.b=24
küp açılımı: a3 – b3 = (a – b) (a2 + ab + b2 ) ise yerleştirelim
(a-b)2= a2-2ab+b2=5.5
a.byi biliyoruz: 24
a2+b2=25+48=73 ise bir de abyi eklediğimizde ikinci çarpanı buluruz
73+24=97
(a-b)= 5 ise a3-b3= ( 5 ) . ( 97) = 485 olur.
a.b=24
a-b=5
(a-b)(a^2+ab+b^2)
(a-b)^2=25=a^2-2ab+b^2
25+2ab=a^2+b^2
a^2+b^2=73
5.(73+24)=5.97=485 olur
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