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f(n)=[tex]\frac{n}{5}[/tex].f(n+1) ve f(2)=[tex]\frac{3}{5}[/tex] ise f(4)=?

Sagot :

Dnzalknrans

[tex]f(n)=\frac{n}{5}.f(n+1) \\ \\f(2)=\frac{2}{5}.f(3) \\ \\\frac{3}{5}=\frac{2}{5}.f(3) \\ \\f(3)=\frac{3}{2} \\ \\f(3)=\frac{3}{5}.f(4) \\ \\\frac{3}{2}=\frac{3}{5}.f(4) \\ \\f(4)=\frac{5}{2}[/tex]

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