[tex](4-\frac{1}{7})^2=16-\frac{8}{7}+\frac{1}{49} \\ \\(x+\frac{1}{4})^2=x^2+\frac{x}{2}+\frac{1}{16} \\ \\(\frac{1}{3}+t)^2=\frac{1}{9}+\frac{2t}{3}+t^2 \\ \\(\frac{1}{5x}+\frac{1}{3})^2=\frac{1}{25x^2}+\frac{2}{15x}+\frac{1}{9} \\ \\(4x-3)^2=16x^2-24x+9 \\ \\(a-5b)^2=a^2-10ab+25b^2 \\ \\(3-\frac{x}{2})=9-3x+\frac{x^2}{4} \\ \\(4+5k)^2=16+40k+25k^2[/tex]
